I'm curous about this problem. The reaction involves finding the major and minor product of an E2 reaction which seems straight forward. However, the hydrogen adjacent to the benzen ring is on the same side as the Bromine leaving group. Wouldn't this mean that removing that hydrogen to form a double bond give us the minor product since the leaving group and abstracted hydrogen have to be anti-periplanar to each other?

This H and Br are on the single bonded carbon atoms and on this bond free rotation is permitted.
C-C single bond can undergo rotation and change the position of H and Br with respect to each other.
In the rings where free rotations are not permitted then we need to have H anti -coplanar to the the leaving group.