Zinc reacts with hydrochloric acid according to the following reactions equation:
Zn + 2HCl ---> ZnCl2 + H2
How many milliliters of 2.00 M HCl are required to react with 2.55 grams of Zn?
Please explain all steps in this process. Thanks! :)
convert gm of Zn = moles of Zn
Moles of Zn into moles of HCl
knowing from balanced equation
1mole of Zn = 2 moles of HCl
now moles of HCl = Molarity X volume
from here calculate volume
1.) 2 HCl + Mg ----> MgCl2 + H2
Mg is the metal...... metals are
alwayz on d left
of the periodic table.
grp1-3.
MgCl2 is the salt
2.) HCl + NaOH ----> NaCl + H2O
NaOH is d base
Nacl is the salt
3.) 2HCl + MgCO3 -------> MgCl2 + CO2 + H2O
-Metal carbonate always consist of a metal and a -CO3
-there are just some bases and acids you have 2 cram bcuz there is no way of knowin except test in d lab.....but most of the times, A hydroxide (-OH) is always a base.
A base is proton acceptor.