Hi,

In 13-C NMR, when a carbon on an aromatic ring is closer to a halogen such as Bromine than another carbon, does that make it a higher or lower ppm?

Thanks!!

Bromine is very electronegative and Carbon of the ring bonded next to bromine atom are strongly deshielded. This results in shifting of the signal to high ppm.

Okay, that makes sense, but the carbons bonded DIRECTLY to the Bromine are supposed to be in the lower 40-50 ppm range, right? So then those carbons are 40-50, and the ones on the ring will then be descending, starting with the highest PPM closest to the bromine, and the lowest at the opposite tip of the ring? The molecule in question is meso-stilbene dibromide.

De-shielded will go to higher ppm

okay now you can see different carbons and the order of the deshielding
1-most and 5 least

pl check this image