Zinc reacts with hydrochloric acid according to the following reactions equation:

Zn + 2HCl ---> ZnCl2 + H2

How many milliliters of 2.00 M HCl are required to react with 2.55 grams of Zn?

Please explain all steps in this process. Thanks! 

convert gm of Zn = moles of Zn
Moles of Zn into moles of HCl
knowing from balanced equation
1mole of Zn = 2 moles of HCl
now moles of HCl = Molarity X volume
from here calculate volume

1.) 2 HCl + Mg ----> MgCl2 + H2

Mg is the metal...... metals are
alwayz on d left
of the periodic table.
grp1-3.

MgCl2 is the salt
2.) HCl + NaOH ----> NaCl + H2O
NaOH is d base
Nacl is the salt

3.) 2HCl + MgCO3 -------> MgCl2 + CO2 + H2O


-Metal carbonate always consist of a metal and a -CO3
-there are just some bases and acids you have 2 cram bcuz there is no way of knowin except test in d lab.....but most of the times, A hydroxide (-OH) is always a base.

A base is proton acceptor.