If the location of a particular electron can be measured only to a precision of 0.046 nm what is the minimum uncertainty in the electron's velocity?  (m=9.109x10^-31 kg, c=3.00x10^8m/s, h=6.63x10^-34 J x s)

How do you work this?

Heisenberg uncertainty principle
delta x X delta p > h/ 4pi

here delta p = m X delta V
m is the mass of the electron
delta V is the uncertainty in velocity
now the precision in position is 0.046nm
it means delta x = 0.046nm
just plug in the values and you will get answer of delta v