Use Hess' law to determine the
H for the following reaction
4 CO(g) + 8H2(g) --> 3CH4(g) + CO2(g) + 2H2O(l)

Given the following information

C(graphite) + 1/2O2(g) -> CO(g)
H = -110:5 kJ
CO(g) + 1/2O2(g) --> CO2(g)
H = -283:5 kJ
H2(g) + 1/2O2(g) --> H2O(l)
H = -285:8 kJ
C(graphite) + 2H2(g) --> CH4(g)
H = -74:81 kJ
CH4(g) + 2O2(g) --> CO2(g) + 2H2O(l)
H = -890:3 kJ

I got -749.5 kj but I think i messed up the mole ratio multiplication at the end.