The catalytic decomposition of hydrogen peroxide is :
  2moles of hydrogen dissolved in water to produce 2moles of water and gas oxygen
Balance the reaction(already done). How many moles of water and oxygen are produced by the decomposition of 68.0 grams of hydrogen peroxide? How many molecules of water and oxygen are produced? How many grams of each product are formed?

Hello,
Here are the answers and how to do the exercise:

Balanced Equation:
2 H202 -> O2 + 2 H20

To answer the questions you can do rule of three.


1) Moles:
2.34g H202.....1 mole O2 + 2 moles H2O
68g H202........ x mole O2 + x mole H2O
x = 1 mole O2 + 2 moles H2O

2.34 = 68, so the number of moles are the same.


2)Molecules:
1 mole 02 = 6.10^23 molecules

1 mole H20....6.1023 molecules
2 mole H20....x molecules
x = 12.10^23 molecules


3)Grams
1 mole 02 = 32g (O = 16g.2=32g)

1 mole H20....18g H20
2 mole H20....xg H20
x = 36g

1 mole H20 --> H=1g.2=2 + O=16 = 18g

Bye,
G97.