Question about Prep of Chemical Solu of known conc

Started by T.O.theYankee, October 01, 2010, 10:30:50 AM

Previous topic - Next topic

0 Members and 1 Guest are viewing this topic.

Print
Go Down Pages1
User actions

T.O.theYankee

October 01, 2010, 10:30:50 AM
In a lab you have 3.0 L of 12 M HCl. How will you prepare2 gallons of0.5 M solution of HCl.

uma

#1
October 04, 2010, 09:01:44 AM
       
1 US gallon = 3.8 L

M1V1 = M2V2
M1= 12M
V1 =?
M2 =0.5M
V2 = 2X3.8 L =7.6L
12X V1 = 0.5 X 7.6
V1 = 0.32 L
dilute 0.32L of 12M acid to 7.6L by adding water
Print
Go Up Pages1
User actions
SMF spam blocked by CleanTalk