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Chemistry Homework Help => General Chemistry => Topic started by: bmathew on December 07, 2009, 12:24:02 PM

Title: Balancing Redox Reaction
Post by: bmathew on December 07, 2009, 12:24:02 PM
VO{2+} (aq) + Zn (s) --->  V{3+} (aq) + Zn{2+} (aq) [in acidic solution]

so V is reduced (+6 --> +3) and Zn is oxidized (0 --> +2). After I seperated the half reactions and balanced the number of electrons out, I ended up with:

2VO{2+} (aq) + 3Zn (s) ---> 2V{3+} (aq) + 3Zn{2+} (aq)

I can't figure out how to balance the charges/the # of H and O atoms after this step.
Title: Re: Balancing Redox Reaction
Post by: uma on December 08, 2009, 02:28:30 AM
okay that's good
You have a session with me on tuesday at 9PM