Volume of gases

Started by Pranjal Singh, November 09, 2020, 09:52:05 AM

Previous topic - Next topic

0 Members and 1 Guest are viewing this topic.

Pranjal Singh

Here it is
[attachment id=0 msg=2684]

uma

#1
QuoteA 100 ml vessel containing O2(g) at 1.0 atm and 400 K is connected toa 300 ml vessel containing NO(g) at
1.5 atm and 400 K by means of a narrow tube of negligible volume where gases react to form NO2. Final pressure of mixture will be-
(A) 1 .125 atm (6) 0.125 atm (C) 1 atm (0) 1.5 atm


[attachment id=0 msg=2781]

O2
P=1atm
V=100mL
T=400K


NO
P=1.5atm
V=300mL
T=400K


Moles of O2 = PV/RT
                   = 1*0.100/RT
                   =    0.1/RT


Moles of NO = PV/RT
                   = 1.5*0.300/RT
                  =  0.45/RT



Balanced  equation is

                        O2  +2 NO       -----> 2NO

Initial moles   0.1/RT     0.45/RT            0


                   Final  moles   0     0.25/RT                  0.20/RT




Total moles finally =  0.25/RT            +      0.20/RT= 0.45/RT   
Total Volume  = 400mL =0.400L   
        P (total)= n(total)RT/V
Plug in all values in proper units
You will get the right answer.

SMF spam blocked by CleanTalk