Nuclear Chemistry

Started by Pranjal Singh, August 13, 2020, 05:51:57 AM

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Pranjal Singh

For the given series reaction in nth step, find out the number of produced neutrons and energy-
238U→Ba+Kr+3n+Energy(E)

uma

Every step releases three neutrons during this decay series.
And it is a chain reaction in which every neutron is going to create a new step to generate 3 more neutrons
It means up to nth step 3n  neutrons are released
Energy for the first step is E .hence E is 3n-1 E

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