Excited state of electronic configurations during molecule bonding

Started by Pranjal Singh, September 29, 2020, 09:34:52 AM

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Pranjal Singh

Here it is
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For the formation of chemical bonds,unpaired electrons are needed for sharing.
Like in case of CH4  there are four bonds around carbon so 4 unpaired electrons are needed in its electronic configuration
However, carbon has two unpaired electrons for sharing in the ground state
1s 2 2S 2 2P2

So it needs to excite one electron from 2s orbital to 2P orbital to have four unshared electrons available for 4 chemical bonds.
In case of BF3 boron has only one unpaired electron in its electronic configuration
1S 22S2 2P1
It also needs to excite one electron from two S to 2p so that it can get three unpaired electrons three chemical bonds.
In case of ICl3, iodine has only one unpaired electron in its ground state so it needs two more unpaired electrons. Electrons will get excited from is 2P orbitals to give three unpaired electrons for making three bonds with Cl.
In case of PCl3 ,P has 3 unpaired electrons in its electronic configuration so all three are available for chemical bonding so there is no need of excited state of electronic configuration in PCl3

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