Q25d 27 and 29

D) Reverse reaction is decomposition reaction which needs heat.hence in D it is exothermic process .If you increase temperature it will shift equilibrium to left .

A and D are the one in which equilibrium does not shift. As volume reduces pressure increases and equilibrium shifts in the direction of low pressure.

29)
A and C are the answers
steam  is the part of equilibrium and hence increase of its pressure will shift the equilibrium on the product side  .
Reaction is endothermic so raising the temperature will shift to right.
however solids  in B) has no effect on K and D) increase in pressure will shift equilibrium in the direction of low pressure.

for Q27 A part why would equilibrium shift if number of moles on both sides are same.
And for B part why would it not shift(the number of moles are different on both sides)
And why would it not shift for C part.

I said equilibrium will not shift  as both sides have same pressure.
I think there is error in teh question
in A and C there is no shifting this is what I have written.

C part I wanted to know why there would be no shift
And for B and D the equilibrium wont shift. Am i right?

I am not sure which question are you talking about....

Q27

27) A and D are the one in which equilibrium does not shift. As volume reduces pressure increases and equilibrium shifts in the direction of low pressure
Check my first answer ...

Question asks in which equilibrium will not shift.