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I need help with this one please

Q = ΔT * c/m

Q = ((27,69-21,36) ?C * 12,3 kJ/?C) /1,55  g = 50,23 kJ/g

Quote from: ann on February 08, 2023, 11:37:34 PM
I need help with this one please

Heat gained by water in bomb calorimeter = heat lost during combustion of propane
q(water) = C Delta t
This is the heat lost by combustion of 1.55 g of propane.
Heat lost by per g = - q(water) /.1.55g