I need some help with these questions
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In bomb calorimeter
q(water ) = C Delta t  = Heat of combustion of 1.535 g CH₃OH
q(water) in  kJ .

∆H = - q (water)/ n
n = moles of methanol.

Quote from: ann on February 08, 2023, 11:29:42 PM
I need some help with these questions
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Enthalpy of formation reaction is
C(s) +2S (s) ---> CS₂---∆H_reaction
Use Hess's law
CS₂ + 3O₂------> CO₂   + 2SO₂--- ∆H₁
S(s)    + O₂ ---> SO₂---∆H₂
C(s)    + O₂ ---> CO₂---∆H₃
∆H_reaction = -∆H₁ +2∆H₂ +∆H₃

Quote from: ann on February 08, 2023, 11:29:42 PM
I need some help with these questions
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This is based on law of conservation of energy.
Heat lost by one system of water at high temperature = heat gained by another system of water(low temperature)
Final temperature of both the systems will be same as they get the thermal equilibrium.Let us assume final temperature is x.
q(lost) =- mc ∆ t = - 100 * 4.18*(x-80)
q(gained) = m ∆H fusion of ice  + mc∆t = 10*335 + 10 4.18(x-0)
Equate these equations to get the value of x .