I have attached the question below
   

Calculate the moles of the nitric acid. According the equation the half will be destroyed to NOx. So the half amount gives then the silver. With molar mass you will get mass.

Quote from: Harini on October 09, 2022, 01:59:55 PM
I have attached the question below

Molarity = moles /volume in L
Use this equation to know the moles of HNO₃.
Now one mole of HNO₃ gives one mole H⁺ .
Planning ---> Mx V (L) moles of HNO₃    ---> Moles  H⁺ ------> moles of Ag+ ------> grams of Ag

QuotePlanning ---> Mx V (L) moles of HNO3    ---> Moles  H+ ------> moles of Ag+ ------> grams of Ag

Should it be like this
Planning ---> Mx V (L) moles of HNO3    ---> Moles  H+ ------> 1/2 moles of Ag+ ------> grams of Ag

One half of the acid is used by the reduction to NOx.

Ag  + 2 H+ + NO3-  => Ag+ + H2O  + NO2

Quote from: chenbeier on October 21, 2022, 05:08:56 PM
Should it be like this
Planning ---> Mx V (L) moles of HNO3    ---> Moles  H+ ------> 1/2 moles of Ag+ ------> grams of Ag

One half of the acid is used by the reduction to NOx.

Ag  + 2 H+ + NO3-  => Ag+ + H2O  + NO2

That's the planning and in planning we don't use numbers.
When students are going to solve it ,then they take molar ratios and molar masses vaules .
Values are not taken in planning.