One of my problems says to draw the Lewis Dot Structure for BeF2, but the formal charge is not zero if I put a double bond between F's and Be. I would do this to complete the octet for all, but does Be not have to have 8 e-? Because if that's the case, I can just put three lone pairs on each F and it would be fine, right?

Solution here

https://topblogtenz.com/beryllium-fluoride-bef2-lewis-structure-molecular-electron-geometry-bond-angle-hybridization/

Quote from: ann on October 05, 2022, 11:22:14 PM
One of my problems says to draw the Lewis Dot Structure for BeF2, but the formal charge is not zero if I put a double bond between F's and Be. I would do this to complete the octet for all, but does Be not have to have 8 e-? Because if that's the case, I can just put three lone pairs on each F and it would be fine, right?

In BeF₂, Be is not with octet and is electron deficient.
Be can give only two electrons for sharing so it can have only two covalent bonds. Fluorine never make a double bond and is always single bonded in its compounds.
[attachment id=0 msg=3412]