I got this wrong while doing a quiz. I think I drew the structures incorrectly, can I get some guidance as to how I should properly do this?
   [attachment id=0 msg=3449]

In ClO2 - each oxygen carries 2 negativ charges, so the equation is

-1= 2*(-2) + (Cl) => Cl = +3

For ClO3- the same calculation gives + 5

-1= 3*(-2) + (Cl) => Cl = +5

Quote from: ann on October 17, 2022, 02:34:24 PM
I got this wrong while doing a quiz. I think I drew the structures incorrectly, can I get some guidance as to how I should properly do this?

Formal Charge = Valence electrons - [ electrons used in bonding + electrons used as lone pairs]
FC = VE - # of bonds - 2*LP

If the Lewis dot structures are like this
[attachment id=0 msg=3457]

Quote from: chenbeier on October 17, 2022, 10:57:28 PM
In ClO2 - each oxygen carries 2 negativ charges, so the equation is

-1= 2*(-2) + (Cl) => Cl = +3

For ClO3- the same calculation gives + 5

-1= 3*(-2) + (Cl) => Cl = +5

This you have calculated the oxidation numbers .