Can you please advise if the below is correct?

--Decrease in Volume will shift Equilibrium towards the Left. Because when Volume is decreased there will be Fewer molecules of reactants and the Equilibrium will shift to the Left.[Q>K]

-- Increase in Volume --will result in more moles of Reactants. So Equilibrium will shift to Right.
[Q<K]

Dependence on the reaction.

N2 + 3 H2 => 2  NH3
Decrease of volume shift to right.
2 SO3 => 2 SO2 + O2
Decrease of volume shift to left

Quote from: prasamb@yahoo.com on January 18, 2023, 10:48:48 AM
Can you please advise if the below is correct?

--Decrease in Volume will shift Equilibrium towards the Left. Because when Volume is decreased there will be Fewer molecules of reactants and the Equilibrium will shift to the Left.[Q>K]

-- Increase in Volume --will result in more moles of Reactants. So Equilibrium will shift to Right.
[Q<K]

Change in volume can be related to change in pressure.
As Volume decreases , pressure increases so equilibrium shifts in the direction of low pressure.
As volume increases , pressure decreases so equilibrium  shifts in the direction of high pressure.
Now how to identify low pressure and high pressure side of the equilibrium?
Like in case of 
N₂(g) + 3H₂(g) <---> 2NH₃ (g)
Here right side of equilibrium is with 2 moles of gas and left side has 4 moles of gas. So left side is at high pressure and right side is at low pressure.