please see attached file:)
I am confused on how to determine the answer, and what fold means.
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From the slow step
Rate law = k[H2] [IBr]
Reaction is first order with respect to H2 and IBr
As concentration is doubled for H2 and IBr ,rate gets doubled with respect to both of them .
So it will increase 4 folds - due to doubled conc H2 and doubled IBr