determining rate law

Started by ann, January 21, 2023, 07:58:23 PM

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ann

please see attached file:)

I am confused on how to determine the answer, and what fold means.
[attachment id=0 msg=3609]

uma

From the slow step
Rate law = k[H2] [IBr]
Reaction is first order with respect to H2 and IBr
As concentration is doubled for H2 and IBr ,rate gets doubled with respect to both of them .
So it will increase 4 folds - due to doubled conc H2 and doubled IBr

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