(a) 1.27 gallon of paint covers the wall area of 13.2 ft long and 14.5 ft wide. How thick is the paint in mm?

(b) The contents of one 40-lb bag of topsoil can cover 10.0 square feet of ground to a depth of 1.00 in. How many bags are needed to cover a plot that measures 247.98 meters by 170.00 meters to a depth of 4.0000 cm?

(c) The Deepwater Horizon oil rig located off the coast of Louisiana exploded on April 20, 2010, killing 11 workers and triggering a massive oil spill from the ruptured well. The National Oceanic and Atmospheric Administration estimated that about 3.00 gallons of crude oil began spilling into the Gulf of Mexico per second. The first traces of color from an oil slick on the surface of the water appear when the film reaches a thickness of 0.000150 mm and a dark sheet appears once the thickness grows to 0.00200 mm. How many days would it take the ruptured oil well to produce a dark sheet the size of Louisiana (51885 mi2)?

Hi
I have a problem in organic chemistry which I need help with.

What reagent(s) would be appropriate to accomplish the conversion shown?

The options are:
A. HCl
B. HNO3
C. H2SO4
D. HBr
E. K2Cr2O7 + H2SO4

Reaction is
2 Al(s) + 2 KOH(aq) + 6 H2O ---> 2 K[Al(OH)4](aq) + 3 H2(g)
It means two moles are reacting with two moles of KOH
No moles of KOH = molarity X volume in L
= 1.6 X .013L
No of moles of Al = 1.6 X .013L
Multiply it by molar mass of Al to take out the mass

We are going to be synthesizing common alum in lab on thursday. We have prelab questions due by then. The first question is:

What mass of pure aluminum can be dissolved by 13 mL of 1.6M KOH?

I know that there is a 1:1 ratio of Al and KOH when the equation is balanced, but beyond that, I'm not sure exactly how to calculate this.

The other questions I can figure out once I get this mass.

Thank you!

yes nearly 40L

ok thanks. I ended up with v=39.9L. pretty sure thats right so thank you for the help.

Number of moles = mass/ molar mass
now mass =50.0 g
molar mass =28.02 g
just plug in these values
At STP
T = 273K
P = 1atm
V =?
n = 50/ 28.02
plug in these values in the ideal gas equation
PV = nRT
V = nRT/P
R = 0.0821Latm/mol.K

Ok so I have this problem on my Chemistry homework. it states.

1.00 moles of nitrogen gas has a mass of 28.02g. What is the volume of 50.0g of nitrogen gas at STP?

I have the formula to work it out. I just don't know how to figure out how many moles 50.0g of nitrogen gas is.

Any ideas?

If you have posted  that means your account is activated

Hi there, I dont know if I am writing in a proper board but I have got a problem with activation, link i receive in email is not working... [url=http://chemtopper.com/?88f3d8382c77eeff7e718faa25b]http://chemtopper.com/?88f3d8382c77eeff7e718faa25b[/url],